Oct 1, 2012 · In Regex, . refers to any character, be it a number, an aplhabet character, or any other special character. * means zero or more times.

In regex in general, ^ is negation only at the beginning of a character class. Unless CMake is doing something really funky (to the point where calling their pattern matching language "regex" could be …

Javascript RegExp () allows you to specify a multi-line mode (m) which changes the behavior of ^ and $. ^ represents the start of the current line in multi-line mode, otherwise the start of the string $ …

Jan 2, 1999 · Parentheses in regular expressions define groups, which is why you need to escape the parentheses to match the literal characters. So to modify the groups just remove all of the unescaped …

Nov 13, 2021 · How do I create a regular expression to match a word at the beginning of a string? We are looking to match stop at the beginning of a string and anything can follow it. For example, the …

While writing this answer, I had to match exclusively on linebreaks instead of using the s-flag (dotall - dot matches linebreaks). The sites usually used to test regular expressions behave diffe...

Repetition in regex by default is greedy: they try to match as many reps as possible, and when this doesn't work and they have to backtrack, they try to match one fewer rep at a time, until a match of …

Apr 5, 2009 · I found a blogpost from 2007 which gives the following regex that matches string which don't contains a certain substring: ^((?!my string).)*$ It works as follows: it looks for zero or more (*) …

Aug 18, 2010 · What is also important there is that regex with non-capturing groups (?: is much faster than the same regex with capturing groups ' ('. So we should use non-capturing groups when we …

Oct 16, 2009 · Quick answer: ^[\w*]$ will match a string consisting of a single character, where that character is alphanumeric (letters, numbers) an underscore (_) or an asterisk (*). Details: The " \w " …